Question concerning the definition of pump-probe signal
Posted: Thu Jul 13, 2023 2:51 am
Dear all,
In the paper "Exciton-exciton transitions involving strongly bound excitons: An ab initio approach, PRB, 107, 205203 (2023)" and tutorial "https://www.yambo-code.eu/wiki/index.ph ... note-pnp-1" the pump and probe simulation gives the result as "the pump&probe minus the one of generate by the pump only", namely, Delta_P(t)=P_PnP(t)-P_pump(t).
In experiment we usually monitor the signal difference of the PROBE beam with and without pump as a function of the time delay (t_delay) between the PROBE beam and the PUMP beam. That is, Delta_I(t_delay)=I_PnP(t_delay)-I_PROBE(t_delay), where I_PnP is the intensity of PROBE beam with Pump and I_PROBE is the intensity of PROBE beam without pump. For example, the setup introduced in https://pubs.acs.org/doi/10.1021/acsnano.5b06488
My question is why in the simulation the P_pump (t) was used to in the subtraction rather than P_PROBE(t).
Zhipeng Huang
Tongji University, PR China
In the paper "Exciton-exciton transitions involving strongly bound excitons: An ab initio approach, PRB, 107, 205203 (2023)" and tutorial "https://www.yambo-code.eu/wiki/index.ph ... note-pnp-1" the pump and probe simulation gives the result as "the pump&probe minus the one of generate by the pump only", namely, Delta_P(t)=P_PnP(t)-P_pump(t).
In experiment we usually monitor the signal difference of the PROBE beam with and without pump as a function of the time delay (t_delay) between the PROBE beam and the PUMP beam. That is, Delta_I(t_delay)=I_PnP(t_delay)-I_PROBE(t_delay), where I_PnP is the intensity of PROBE beam with Pump and I_PROBE is the intensity of PROBE beam without pump. For example, the setup introduced in https://pubs.acs.org/doi/10.1021/acsnano.5b06488
My question is why in the simulation the P_pump (t) was used to in the subtraction rather than P_PROBE(t).
Zhipeng Huang
Tongji University, PR China