Dear all,
In the paper "Exciton-exciton transitions involving strongly bound excitons: An ab initio approach, PRB, 107, 205203 (2023)" and tutorial "https://www.yambo-code.eu/wiki/index.ph ... note-pnp-1" the pump and probe simulation gives the result as "the pump&probe minus the one of generate by the pump only", namely, Delta_P(t)=P_PnP(t)-P_pump(t).
In experiment we usually monitor the signal difference of the PROBE beam with and without pump as a function of the time delay (t_delay) between the PROBE beam and the PUMP beam. That is, Delta_I(t_delay)=I_PnP(t_delay)-I_PROBE(t_delay), where I_PnP is the intensity of PROBE beam with Pump and I_PROBE is the intensity of PROBE beam without pump. For example, the setup introduced in https://pubs.acs.org/doi/10.1021/acsnano.5b06488
My question is why in the simulation the P_pump (t) was used to in the subtraction rather than P_PROBE(t).
Zhipeng Huang
Tongji University, PR China
Question concerning the definition of pump-probe signal
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Re: Question concerning the definition of pump-probe signal
Dear Zhipeng Huang,
from the Fourier transform of we obtain the frequency dependent polarization and later the signal in presence of the pump This procedure is used in many work in the literature and is also what is done for the post-processing of the analysis of the experimental data.
It gives you what you define as "I_PnP(omega,t_delay)" (I added the frequency dependence)
If the signal is detected in an energy range where there is absorption at equilibrium, usually the equilibrium signal is subtracted to obtain the transient signal.
What you express as "Delta_I(omega,t_delay)=I_PnP(omega,t_delay)-I_PROBE(omega)" (I probe does not depend on t_delay)
See for example this work: https://doi.org/10.1103/PhysRevMaterials.5.083803 where the above mentioned procedure is used, and later the equilibrium spectrum is removed to obtain the transient signal (figure 5 in the manuscript).
In the paper "Exciton-exciton transitions involving strongly bound excitons: An ab initio approach, PRB, 107, 205203 (2023)" instead we focus on an energy range where I_PROBE(omega)=0
Best,
D.
from the Fourier transform of we obtain the frequency dependent polarization and later the signal in presence of the pump This procedure is used in many work in the literature and is also what is done for the post-processing of the analysis of the experimental data.
It gives you what you define as "I_PnP(omega,t_delay)" (I added the frequency dependence)
If the signal is detected in an energy range where there is absorption at equilibrium, usually the equilibrium signal is subtracted to obtain the transient signal.
What you express as "Delta_I(omega,t_delay)=I_PnP(omega,t_delay)-I_PROBE(omega)" (I probe does not depend on t_delay)
See for example this work: https://doi.org/10.1103/PhysRevMaterials.5.083803 where the above mentioned procedure is used, and later the equilibrium spectrum is removed to obtain the transient signal (figure 5 in the manuscript).
In the paper "Exciton-exciton transitions involving strongly bound excitons: An ab initio approach, PRB, 107, 205203 (2023)" instead we focus on an energy range where I_PROBE(omega)=0
Best,
D.
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Davide Sangalli, PhD
CNR-ISM, Division of Ultrafast Processes in Materials (FLASHit) and MaX Centre
https://sites.google.com/view/davidesangalli
http://www.max-centre.eu/
CNR-ISM, Division of Ultrafast Processes in Materials (FLASHit) and MaX Centre
https://sites.google.com/view/davidesangalli
http://www.max-centre.eu/
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Re: Question concerning the definition of pump-probe signal
Dear Davide Sangalli
Thank you very much for the reply.
Zhipeng Huang
Tongji University, PR China
Thank you very much for the reply.
Zhipeng Huang
Tongji University, PR China