Yambo Community Forum

Dear developers,
I am running SHG with Yambo and got the SHG chi, and how could I obtain the imaginary part of the dielectric constant at both
ω/2 and ω? (As in attached, the red solid and dashed lines)



Thanks!

Rongtian

Do you mean the imaginary part of the dielectric constant or SHG?
The dielectric constant is linear optical paramater and not SHG.

Dear Zhao,
I think it is the imaginary part of the dielectric. How to obtain the dielectric constant at ω/2?

Thanks!

Rongtian

please see the first tutorial at http://www.attaccalite.com/lumen/tutorials.html.

I notice that just an abs. of ω instead of ω/2?

Thanks!
Rongtian

I think the abs. of ω/2 is just to extend the abs. of ω in the picture, ie. f(x/2) compared with f(x).
So there is no specially abs. of ω/2 in the output file from yambo. We just read abs. ω and then recalculate it.

Best.

Dear Rongtian

once you have the imaginary part of the dielectric constant, just plot it with the argument divided by two
for example in python:


plt.plot(EPS[:,0]/2., EPS[:,1],color="red", linewidth=3.0, linestyle="-", label="$\epsilon_2(\omega/2)$")
plt.plot(EPS[:,0], EPS[:,1],color="red", linewidth=3.0, linestyle="--",label="$\epsilon_2(\omega)$")

best
Claudio