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Yambo Kerr

Posted: Thu Mar 28, 2019 11:20 am
by michele guerrini
Dear developers, I would need to perform optical simulations at RPA level resolved in polarization and then to access (or extract in a log file) the full dielectric tensor by using three orthogonal polarizations per each frequency. I know there is the routine Yambo_kerr but, since I have never used it before, I was wondering how should I proceed.

Many thanks!

Michele

Re: Yambo Kerr

Posted: Thu Mar 28, 2019 1:03 pm
by Davide Sangalli
Dear Michele,
it depends a bit on what you need to compute.

OPT 1
yambo kerr is able to directly compute the off-diagonal matrix elements of the dielectric tensor.
But i is limited to the xy plane. It works as follow.
(i) prepare the input file for a calculation in eh space (yambo -o b) using yambo_kerr in place of yambo
(ii) uncomment the EvalKerr flag
(iii) specify the direction "i" along which you want to compute the dielectric function. It must lie in the xy plane
For "i=x"

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% BLongDir
 1.000000 | 0.000000 | 0.000000 |        # [BSS] [cc] Electric Field
%
yambo_kerr will give you in output eps_ii and eps_ij where "j" is the direction rotated by 90 degree (in the xy plane) compared to i.
Accordingly "i=x" then "j=y".

OPT 2
Alternatively you can do six standard calculations with yambo specifying each time a different direction and then reconstruct the whole dielectric tensor.
Yo will need (1,1,0), (1,0,1), (1,0,0), (0,1,1), (0,1,0) and (0,0,1). There are relations you can find in the literature.
Again the relevant variable is

Code: Select all

% BLongDir
 1.000000 | 0.000000 | 0.000000 |        # [BSS] [cc] Electric Field
%
In this second case you will obtain only the symmetric part of the off diagonal elements, while in the first there will be an eventual contribution from the anti-symmetric part in case it exist in your system (for example in presence of a magnetizaton and SOC or of an external magnetic field)

Best,
D.

Re: Yambo Kerr

Posted: Thu Mar 28, 2019 2:42 pm
by michele guerrini
Dear Davide,
thank you very much for the advices. So, regarding Option 1 you are suggesting, if I would like to calculate the component eps_yz, I should choose to polarize the E field along i=y and for component eps_zx , along i=z ? Right ?

Bests

Michele

Re: Yambo Kerr

Posted: Thu Mar 28, 2019 3:53 pm
by Davide Sangalli
Option one, for now, is limited to compute eps_xy basically.
So a way to get eps_yz without touching the code would be to rotate the atoms in the supercell, in such a way that "x" beomes "y" and "z" becomes "y" ...

Otherwise one could change the code. It is quite easy.
Just open the subroutine
src/pol_function/DIPOLE_project_along_q.F

Then "field_dir" is the direction defined in the input (what I called "i") and "dipole_dir" is the direction rotated by 90_degrees (what I called "j").
You can just manually change the two to get the ij component you prefer.
Pay attention to the "q0_def_norm" factor.

Re: Yambo Kerr

Posted: Wed Jan 07, 2026 5:41 pm
by Ehsanulazim
Hi Professor,

Would anybody please suggest any reference to find the relation:
Yo will need (1,1,0), (1,0,1), (1,0,0), (0,1,1), (0,1,0) and (0,0,1). There are relations you can find in the literature.
I tried a lot but couldn't find very specific relation for that. Would it be something as follows

Lets say for eps_xy and eps_yz:

eps_xy = eps @(1,1,0) - [eps @(1,0,0)+eps @(0,1,0) / 2]
eps_yz = eps @(0,1,1) - [eps @(0,1,0)+eps @(0,0,1) / 2]

Thank you

Best regards
Ehsanul Azim
MSc, Mechanical Engg, UTRGV, USA

Re: Yambo Kerr

Posted: Thu Jan 08, 2026 12:28 am
by Davide Sangalli
Dear Ehsanul Azim,

I have some old notes with the following relations (right now I do not find the reference to them)
Dielectric_tensor_relations.png
However, with the more recent implementation (yambo 5.3 for example) you can directly get all matrix elements of the dielectric tensor.
By setting in input

Code: Select all

BSEprop="abs kerr"
you will get epsilon_{ii} and epsilon_{ij} with j an axis rotated by 90° w.r.t. i

The "i" axis is determined by

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 % BLongDir
  1.000000 | 0.000000 | 0.000000 |        # [BSS] [cc] Electric Field
 %
 
The "j" axis is determined by

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BSEdips="xy"  # [BSS] Can be "trace/none" or "xy/xz/yz" to define off-diagonal rotation plane  
The two values above are to get epsilon_{xx} and epsilon_{xy}
By setting "xz" you would get also epsilon_{xz}.

Similarly you can put "yx" and "yz" with

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 % BLongDir
  0.000000 | 1.000000 | 0.000000 |        # [BSS] [cc] Electric Field
 %
 
"zx" and "zy" with

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 % BLongDir
  0.000000 | 0.000000 | 1.000000 |        # [BSS] [cc] Electric Field
 %
 
See also here: https://www.lumen-code.org/wiki/index.p ... err_effect


Please double check the output, because this part of the code is not used very much. The values of BSE_dipole_geometry are given in input to the subroutine "v_rotate" inside src/modules/mod_vec_operate.F, called by src/bse/K_dipoles.F
You can easyly check the code there

Best,
D.

Re: Yambo Kerr

Posted: Thu Jan 08, 2026 4:44 pm
by Ehsanulazim
Hi Professor,

Thank you so much for your reply. Would you please check whether the following statement is right or wrong? I want to make sure that I am going in the right direction.

If we want to calculate dielectric tensor for anisotropic materials where ϵ_ij or ϵ_ji is not equal to zero,
1) If the material is nonmagnetic and symmetric (ϵ_ij = ϵ_ji), we can use the six standard calculations in reciprocal space. Even if the material is magnetic and it has a symmetric part (ϵ_ij = ϵ_ji), we can use the six standard calculations.
2)If the material is magnetic and antisymmetric (ϵ_ij != ϵ_ji), we should use Yambo Kerr in the e–h space.


Thank you

Best regards
Ehsanul Azim
MSc, Mechanical Engg, UTRGV, USA

Re: Yambo Kerr

Posted: Thu Jan 08, 2026 5:23 pm
by Davide Sangalli
Dear Ehsanul Azim,
I think you are right.

Indeed, the kerr would be proportional, in the most general case, to the anti-symmetric term eps^A_{ij} = 1/2 (eps_{ij} - eps_{ji})